Question

For a transistor the parameter β = 99. The value of the parameter α is

• A. 0.9
• B. 0.99
• C. 1
• D. 9

Answer 1

Answer: (B)

0.99

Answer 2

$\alpha = \frac{\beta}{1 + \beta} = \frac{99}{1 + 99} = 0.99$.