Question
Question: For a transistor, the current amplification factor is 0.8. The transistor is connected in common emi...
For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 mA is.
A
6 mA
B
4.8 mA
C
24 mA
D
8 mA
Answer
24 mA
Explanation
Solution
α = 0.8 ⇒β=(1−0.8)0.8=4
Also β=ΔibΔic⇒Δic=β×Δib= 4 × 6 = 24mA.