Question

For a transistor, in a common emitter arrangement, the alternating current gain $P$ is given by :

• A. $\beta=\left(\frac{\Delta I_{C}}{\Delta I_{B}}\right)_{V_{C E}}$
• B. $\beta=\left(\frac{\Delta I_{B}}{\Delta I_{C}}\right)_{V_{C E}}$
• C. $\beta=\left(\frac{\Delta I_{C}}{\Delta I_{E}}\right)_{V_{C E}}$
• D. $\beta=\left(\frac{\Delta I_{E}}{\Delta I_{e}}\right)_{V_{C E}}$

Answer 1

Answer: (A)

$\beta=\left(\frac{\Delta I_{C}}{\Delta I_{B}}\right)_{V_{C E}}$

Answer 2

The AC current gain in an common-enitter transistor is denned as the ratio of the change in the collector current to the change in the base current at a constant collector to emitter voltage $\beta=\left(\frac{\Delta i_{C}}{\Delta i_{B}}\right)_{V_{C E}}$