Question
Question: For a transistor amplifier in common emitter configuration for load impedance of 1 kΩ (h<sub>fe</sub...
For a transistor amplifier in common emitter configuration for load impedance of 1 kΩ (hfe = 50 and hoe = 25) the current gain is
A
– 5.2
B
– 15.7
C
– 24.8
D
– 48.78
Answer
– 48.78
Explanation
Solution
In common emitter configuration current gain
Ai=1+hoeRL−hfe=1+25×10−6×103−50= – 48.78.