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Question: For a system in equilibrium, \(\Delta G = 0\) , under conditions of constant______. A.Temperature ...

For a system in equilibrium, ΔG=0\Delta G = 0 , under conditions of constant______.
A.Temperature and pressure.
B.Temperature and volume.
C.Pressure and volume.
D.Energy and volume.

Explanation

Solution

We can use the formula ΔG=ΔG+RTlnK\Delta G = \Delta {G^ \odot } + RT\ln K where ΔG\Delta G is free energy change and ΔG\Delta {G^ \odot } is free energy change under standard conditions,R=8.314 JmolC1R = 8.314{\text{ Jmol}}{{\text{C}}^{ - 1}} is gas constant, T=Temperature and K is equilibrium constant of a reaction. We can also use the formula-
ΔG = ΔH - TΔS\Delta {\text{G = }}\Delta {\text{H - T}}\Delta {\text{S}} where ΔG\Delta {\text{G}} is change in free energy, ΔS\Delta {\text{S}} is entropy change, ΔH\Delta {\text{H}} is enthalpy change and T{\text{T}} is the temperature in Kelvin.

Complete step by step answer:
ΔG\Delta G is Gibbs free energy for a system. It will be zero for a system in equilibrium only if the temperature and pressure are constant. It is also given as –
ΔG=ΔG+RTlnK\Rightarrow \Delta G = \Delta {G^ \odot } + RT\ln K
WhereΔG\Delta {G^ \odot } is free energy change under standard conditions, R=8.314 JmolC1R = 8.314{\text{ Jmol}}{{\text{C}}^{ - 1}} is gas constant, T=Temperature and K is equilibrium constant of a reaction.
Now if ΔG=0\Delta G = 0then we get the free energy change under standard conditions,
ΔG=RTlnK\Rightarrow \Delta {G^ \odot } = - RT\ln K
Gibbs free energy is also given as-
ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S Where ΔH\Delta H= change in enthalpy, ΔS\Delta S is change in entropy and T is the temperature.
We can write-
ΔH=ΔU+PΔV\Delta H = \Delta U + P\Delta V where P is constant pressure, V is volume and U is internal energy.
Then we can write –
ΔG=ΔU+PΔVTΔS\Rightarrow \Delta G = \Delta U + P\Delta V - T\Delta S
In the above equation only pressure and temperature are constant in equilibrium when ΔG=0\Delta G = 0

Hence the correct answer is A.

Note:
The direction of a chemical reaction is indicated by the sign of ΔG\Delta G and it also tells –
If ΔG<0\Delta G < 0 then, the reaction is spontaneous in the direction it is written (backward or forward).This means that no external energy is needed for the reaction to occur.
If ΔG=0\Delta G = 0 then, the system is at equilibrium. No changes occur in either forward or backward direction.
If ΔG>0\Delta G > 0 then the reaction is not spontaneous. This means the reaction needs input of free energy to make the reaction go forward instead of backward.