Solveeit Logo

Question

Question: For a stretched string of given length, the tension \(T\) is plotted on the X-axis and the frequency...

For a stretched string of given length, the tension TT is plotted on the X-axis and the frequency ff on the Y-axis. The graph has the shape of a
A) Rectangular Hyperbola
B) Straight through the origin
C) Parabola
D) Straight line not through the origin

Explanation

Solution

Whenever a string is stretched under tension, transverse waves can travel on the string. Use the formula of the speed of waves on a string and use the relation between frequency and speed to determine the shape of the graph.

Formula used:
v=Tμ\Rightarrow v = \sqrt {\dfrac{T}{\mu }} where vv is the velocity of waves on a string, TT is the tension on the string, and μ\mu is the linear mass density of the string.
v=L×f\Rightarrow v = L \times fwhere LL is the length of the string and ff is the frequency of the waves traveling on the string

Complete step by step solution:
A wave can travel on a string under tension with a speed:
v=Tμ\Rightarrow v = \sqrt {\dfrac{T}{\mu }}
Since we’ve been asked to find the relation between frequency and Tension, we will use the relation between velocity and frequency v=L×fv = L \times f whereLL is the length of the string andff is the frequency of the waves traveling on the string.
Substituting the value of v=Tμv = \sqrt {\dfrac{T}{\mu }} in v=L×fv = L \times f, we get:
Tμ=L×f\Rightarrow \sqrt {\dfrac{T}{\mu }} = L \times f
On squaring both sides, we get
Tμ=L2×f2\Rightarrow \dfrac{T}{\mu } = {L^2} \times {f^2}
Dividing both sides by L2{L^2} , we get:
f2=TμL2\Rightarrow {f^2} = \dfrac{T}{{\mu {L^2}}}
This equation can be written in the form of
f2=4aT\Rightarrow {f^2} = 4aT , where a=14μL2a = \dfrac{1}{{4\mu {L^2}}} is a constant dependent on string mass and length.
This equation has the form of
y2=4ax\Rightarrow {y^2} = 4ax which is the equation of a parabola.
Hence If we plotted the tension TTon the X-axis and the frequency ffon the Y –axis, we will have the shape of a parabola which corresponds to option (C).

Note:
The speed of waves on a string is proportional to the tension on the string. So for higher tension on the string, the frequency of the waves travelling on the sting will be higher. This property is often used in musical instruments like the guitar to generate different sounds with different frequencies by tightening the string to increase tension on it (pitch).