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Question

Chemistry Question on Gibbs Free Energy

For a spontaneous reaction the Δ\DeltaG, equilibrium constant (K) and EcellE^{\circ}_{cell} will be respectively :

A

ve,>1,ve-ve, > 1, -ve

B

ve,<1,ve-ve, < 1, -ve

C

+ve,>1,ve+ve, > 1, -ve

D

ve,>1,+ve-ve, > 1, +ve

Answer

ve,>1,+ve-ve, > 1, +ve

Explanation

Solution

ΔG=2.303RTlogKeq\Delta G^{\circ} = -2.303RT\,log\,K_{eq} ΔG=nFEcell\Delta G^{\circ } = -nFE^{\circ}_{cell} If a cell reaction is spontaneous (proceeding in forward side), it means Keq>1K_{eq} > 1 and Ecell=+veE^{\circ }_{cell} = +ve ThusΔG=ve\quad\quad\Delta G^{\circ } = - ve