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Question

Physics Question on Oscillations

For a simple pendulum, a graph is plotted between its Kinetic Energy (KE) and Potential Energy (PE) against its displacement d. Which one of the following represents these correctly? (graphs are schematic and not drawn to scale)

A

B

C

D

Answer

Explanation

Solution

Taking minimum potential energy at mean position to be zero, the expression of KE and PE are KE=12m?2(A2d2)KE=\frac{1}{2}m?^2(A^2-d^2) and PE=12m?2d2PE=\frac{1}{2}m?^2d^2
Both graphs are parabola. At d = 0, the mean position PE = 0 and KE=12mω2A2KE=\frac{1}{2}m \omega^2 A^2 =maximum
At d=?A,d=?A, the extreme positions,
KE = 0 and PE=12mω2A2PE=\frac{1}{2}m \omega^2 A^2 =maximum
Therefore, the correct graph is (a).