Question

For a series LCR circuit the power loss at resonance is

• A. $V^2[\omega L-\frac{1}{\omega C}]$
• B. I2Lω
• C. I2R
• D. $\frac{V^2}{C\omega}$

Answer 1

Answer: (C)

I2R

Answer 2

The correct option is (C) : I2R

In A.C. circuit power loss P = V I cos φ P = VI = I2R ( ∵ φ = 0 at resonance)