Question

For a satellite escape velocity is $11 \mathrm {~km} / \mathrm { s }$ . If the satellite is launched at an angle of $60 ^ { \circ }$ with the vertical, then escape velocity will be

• A. $11 \mathrm {~km} / \mathrm { s }$
• B. $11 \sqrt { 3 } \mathrm {~km} / \mathrm { s }$
• C. $\frac { 11 } { \sqrt { 3 } } \mathrm {~km} / \mathrm { s }$
• D. $33 \mathrm {~km} / \mathrm { s }$

Answer 1

Answer: (A)

$11 \mathrm {~km} / \mathrm { s }$

Answer 2

Escape velocity does not depend upon the angle of projection.