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Question: For a reaction: X\(\rightarrow\) Y + Z Absolute entropies are X = \(120JK^{- 1}mol^{- 1}\),\(Y = 21...

For a reaction: X→\rightarrow Y + Z

Absolute entropies are X = 120JK−1mol−1120JK^{- 1}mol^{- 1},Y=213.8JK−1mol−1andZ=197.9JK−1mol−1Y = 213.8JK^{- 1}mol^{- 1}andZ = 197.9JK^{- 1}mol^{- 1} will be the entropy change at 298 K and 1 atm?

A

291.7JK−1291.7JK^{- 1}

B

255JK−1255JK^{- 1}

C

213.8JK−1213.8JK^{- 1}

D

257.3JK−1257.3JK^{- 1}

Answer

291.7JK−1291.7JK^{- 1}

Explanation

Solution

: ΔSo=∑SPo−∑SRo\Delta S^{o} = \sum S_{P}^{o} - \sum S_{R}^{o}

=(213.8+197.9)−120=291.7JK−1= (213.8 + 197.9) - 120 = 291.7JK^{- 1}