Solveeit Logo
Login

Question

Chemistry Question on Equilibrium

For a reaction equilibrium, N2O4(g)⇌2NO2(g)N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g ), the concentrations of N2O4N _{2} O _{4} and NO2NO _{2} at equilibrium are 4.8×10−24.8 \times 10^{-2} and 1.2×10−2 mol/L1.2 \times 10^{-2}\, mol / L respectively. The value of kk, for the reaction is:

A

3×10−3 mol/L3 \times 10^{-3} \, mol / L

B

3.3×10−3 mol/L3.3 \times 10^{-3} \, mol / L

C

3×10−1 mol/L3 \times 10^{-1} \, mol / L

D

3.3×10−1 mol/L3.3 \times 10^{-1} \, mol / L

Answer

3×10−3 mol/L3 \times 10^{-3} \, mol / L

Explanation

Solution

The equilibrium constant for the given reaction is- Kc=[NO2]2[N2O4]K _{ c }=\frac{\left[ NO _{2}\right]^{2}}{\left[ N _{2} O _{4}\right]} Kc=(1.2×10−2 mol/L)24.8×10−2 mol/LK _{ c }=\frac{\left(1.2 \times 10^{-2} \,mol / L \right)^{2}}{4.8 \times 10^{-2} \,mol / L } Kc=3×10−3 mol/LK _{ c }=3 \times 10^{-3}\, mol / L