Question

For a reaction, $C_{(s)}+C O_{2}(g) \rightarrow 2 C O_{(g)}$; the partial pressure of $C O_{2}$ and $C O$ are $4$ and $8$ atm, respectively. $K_{p}$ for the reaction is

• A. 0.5
• B. 2
• C. 16
• D. 4

Answer 1

Answer: (C)

16

Answer 2

$C(S)+C O_{2}(g) \rightarrow 2 C O(g)$ Applying the law of mass action
$K_{p}=\frac{\left(p_{C O}\right)^{2}}{\left(p_{C}\right)\left(p_{C O_{2}}\right)}$
Given, $p_{C O}=8$ atm
$p_{C O_{2}}=4$ atm and for solid $C(S) p_{C}=1$
$\therefore K_{p}=\frac{(8)^{2}}{1 \times 4}$
$\Rightarrow K_{p}=\frac{64}{4}=16$