Question

For a reaction between gaseous compounds, \hspace20mm 2A + B \longrightarrow C + D the reaction rate = k[A][B]. If the volume of the container is made $\frac{1}{4}$ of the initial, then what will be the rate of reaction as compared to the initial rate?

• A. 16 times
• B. 4 times
• C. $\frac{1}{8}$ times
• D. $\frac{1}{16}$ times

Answer 1

Answer: (A)

16 times

Answer 2

When volume is reduced to one fourth, concentrations become four times. Hence, the rate of reaction becomes 16 times as compared to the initial rate.