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Question

Chemistry Question on Thermodynamics

For a reaction, A(g)A(l);ΔH=3RT {A_(g) \to A_(l); \Delta H = - 3RT}. The correct statement for the reaction is :

A

ΔH=ΔUO\Delta H = \Delta U \neq O

B

ΔH=ΔU=O\Delta H = \Delta U = O

C

ΔH<ΔU | \Delta H| < | \Delta U|

D

ΔH>ΔU | \Delta H| > | \Delta U|

Answer

ΔH>ΔU | \Delta H| > | \Delta U|

Explanation

Solution

For the reaction A(g)A(l)A ( g ) \rightarrow A ( l ) The change in the number of moles of gaseous species Δn=01=1\Delta n =0-1=-1 The enthalpy change ΔH=3RT\Delta H =-3 RT ΔH=ΔU+ΔnRT\Delta H =\Delta U +\Delta nRT 3RT=ΔU+(1)RT-3 R T=\Delta U+(-1) R T The change in internal energy ΔU=2RT\Delta U =-2 RT Hence, ΔH>ΔU|\Delta H |>|\Delta U |