Question

For a reaction 2A $\rightarrow$ products, the rate constant is found to be 0.0693 $\text{min}^{-1}$. What is the half-life of the process?

Answer 1

10 min

Answer 2

The given rate constant's unit ($\text{min}^{-1}$) signifies a first-order reaction. For a first-order reaction, the half-life ($t_{1/2}$) is calculated using the formula $t_{1/2} = \frac{\ln(2)}{k}$. Substituting the given rate constant $k = 0.0693 \, \text{min}^{-1}$ and $\ln(2) \approx 0.693$, we get $t_{1/2} = \frac{0.693}{0.0693} = 10 \, \text{min}$.