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Question: For a process, the relation between temperature and volume is \[T{V^3}\]= constant. If a monatomic g...

For a process, the relation between temperature and volume is TV3T{V^3}= constant. If a monatomic gas follows this process, find molar specific heat for this process
A. 7R6\dfrac{{7R}}{6}
B. R3\dfrac{R}{3}
C. All of this
D. none of this

Explanation

Solution

The process is polytropic. In this process we see that PVnP{V^n} = constant. Ratio of specific heat is γ=CPCV\gamma = \dfrac{{CP}}{{CV}} is a factor in adiabatic processes and it helps in determining speed in gases. This ratio for an ideal monatomic gas is γ=1.66\gamma = 1.66 and for air it is γ=1.4{\text{ }}\gamma = 1.4, which a diatomic gas usually is. Gamma is seen in many fluids equations which are generally related to pressure or temperature, and volume during a compression or expansion process.
Formula used :
c=(Rγ1)+(R1n)c = \left( {\dfrac{R}{{\gamma - 1}}} \right) + \left( {\dfrac{R}{{1 - n}}} \right)
Where,
R is universal gas constant.
T is the temperature
P is the pressure
V is the volume
Gamma is an adiabatic exponent.

Complete step by step answer:
As we know that,
PV=nRTPV = nRT
TV3T{V^3}= Constant
(PVnR)×V3\left( {\dfrac{{PV}}{{nR}}} \right) \times {V^3}= Constant
PV4P{V^4}=Constant
n is 4 in the above equation
we know that in monatomic gas is γ=CPCV\gamma = \dfrac{{CP}}{{CV}}
in monoatomic gas 32\dfrac{3}{2}
γ=5R23R2\gamma = \dfrac{{5\dfrac{R}{2}}}{{3\dfrac{R}{2}}}
On simplification we get,
γ=53\gamma = \dfrac{5}{3}
Now we will substitute the values in the formula that we know
c=(R1531)+(R14)c = \left( {\dfrac{{\dfrac{R}{1}}}{{\dfrac{5}{3} - 1}}} \right) + \left( {\dfrac{R}{{1 - 4}}} \right)
On simplification we get,
c=7R6c = \dfrac{{7R}}{6}
So option A is the correct option for the given question. Option A is 7R6\dfrac{{7R}}{6} . So this is the correct option. Other options are invalid. Option D is wrong as we have one option correct. Option B is also incorrect as the value is different. Hence Option C is also not valid in this situation.
So, the correct answer is Option (A).

Note:
-We have to know that there are different kinds of gases like monoatomic diatomics and many more like that. There various formulae used to know more about these gases.
-We must remember that monatomic gases are gases composed of particles that have single atoms, for example helium or sodium vapour, and in this way different from polyatomic gases.
-Diatomic molecules are other molecules which are composed of only two atoms, they can be the same or different.