Question
Question: For a process, the relation between temperature and volume is \[T{V^3}\]= constant. If a monatomic g...
For a process, the relation between temperature and volume is TV3= constant. If a monatomic gas follows this process, find molar specific heat for this process
A. 67R
B. 3R
C. All of this
D. none of this
Solution
The process is polytropic. In this process we see that PVn = constant. Ratio of specific heat is γ=CVCP is a factor in adiabatic processes and it helps in determining speed in gases. This ratio for an ideal monatomic gas is γ=1.66 and for air it is γ=1.4, which a diatomic gas usually is. Gamma is seen in many fluids equations which are generally related to pressure or temperature, and volume during a compression or expansion process.
Formula used :
c=(γ−1R)+(1−nR)
Where,
R is universal gas constant.
T is the temperature
P is the pressure
V is the volume
Gamma is an adiabatic exponent.
Complete step by step answer:
As we know that,
PV=nRT
TV3= Constant
(nRPV)×V3= Constant
PV4=Constant
n is 4 in the above equation
we know that in monatomic gas is γ=CVCP
in monoatomic gas 23
γ=32R52R
On simplification we get,
γ=35
Now we will substitute the values in the formula that we know
c=35−11R+(1−4R)
On simplification we get,
c=67R
So option A is the correct option for the given question. Option A is 67R . So this is the correct option. Other options are invalid. Option D is wrong as we have one option correct. Option B is also incorrect as the value is different. Hence Option C is also not valid in this situation.
So, the correct answer is Option (A).
Note:
-We have to know that there are different kinds of gases like monoatomic diatomics and many more like that. There various formulae used to know more about these gases.
-We must remember that monatomic gases are gases composed of particles that have single atoms, for example helium or sodium vapour, and in this way different from polyatomic gases.
-Diatomic molecules are other molecules which are composed of only two atoms, they can be the same or different.