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Question

Physics Question on Ray optics and optical instruments

For a plane convex lens (µ=1.5)(µ = 1.5) has radius of curvature 10 cm. It is silvered on its plane surface. Find focal length after silvering:

A

10 cm10\ cm

B

20 Cm20\ Cm

C

15 cm15 \ cm

D

25 cm25 \ cm

Answer

10 cm10\ cm

Explanation

Solution

Equivalent power of combination

Peq=2PL+PMP_{eq}=2P_L+P_M

PeqP_{eq} =2(µ–1)(1R)+02(µ–1)(\frac 1R)+0

The required focal length

f=1Peqf=–\frac {1}{P_{eq}}

f=R2(μ1)f =–\frac {R}{2(μ-1)}

f=102(1.51)f =–\frac {10}{2(1.5-1)}

f=10 cmf =–10\ cm

So, the correct option is (A): 10 cm10\ cm