Question

For a party $8$ guests are invited by a husband and his wife. They sit in a row for dinner. The probability that the husband and his wife sit together is

• A. $\frac{2}{7}$
• B. $\frac{2}{9}$
• C. $\frac{1}{9}$
• D. $\frac{4}{9}$

Answer 1

Answer: (B)

$\frac{2}{9}$

Answer 2

Total number of way of sitting $=9 !$
and number of favourable ways of sitting $=2 \times 8 !$
$\therefore$ Required probability $=\frac{2 \times 8 !}{9 !}=\frac{2}{9}$.