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Question: For a particular reversible reaction at temperature T, \(\Delta\)H and \(\Delta\)S were found to be ...

For a particular reversible reaction at temperature T, Δ\DeltaH and Δ\DeltaS were found to be both +ve. If Te is the temperature at equilibrium, the reaction would be spontaneous when.

A

Te> T

B

T > Te

C

Te is 5 times T

D

T = Te

Answer

T > Te

Explanation

Solution

Δ\DeltaG = Δ\DeltaH – TΔ\DeltaS

For spontaneous reaction Δ\DeltaG must be negative

At equilibrium temperature Δ\DeltaG = 0

to maintain the negative value of Δ\DeltaG

T should be greater than Te .