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Question: For a particular reaction, DHŗ = – 40 kJ and DSŗ = – 200 J K<sup>–1</sup>mol<sup>–1</sup>. The react...

For a particular reaction, DHŗ = – 40 kJ and DSŗ = – 200 J K–1mol–1. The reaction is

A

Spontaneous at all temperatures

B

Non-spontaneous at all temperatures

C

Spontaneous at temperature below – 73ŗ C

D

Spontaneous at temperature above – 73ŗ C

Answer

Spontaneous at temperature above – 73ŗ C

Explanation

Solution

DG0 = DH0 – TDS0

When DG0 = 0, T = ΔHºΔSº\frac{\Delta Hº}{\Delta Sº} = 40×103200\frac{- 40 \times 10^{3}}{- 200}= 200 K