Question

For a particle in $SHM$ , if the amplitude of the displacement is a and the amplitude of velocity is $v$ , the amplitude of acceleration is

• A. $va$
• B. $\frac{v^{2}}{a}$
• C. $\frac{v^{2}}{2a}$
• D. $\frac{v}{a}$

Answer 1

Answer: (B)

$\frac{v^{2}}{a}$

Answer 2

$V_{max} =\alpha \omega \,$and
Maximum acceleration = $\omega^2 a$
$=\bigg(\frac{v}{a}\bigg)^2 a=\frac{v^2}{a}$