Question

For a particle executing simple harmonic motion, the kinetic energy K is given by $K = K_{o}\cos^{2}\omega t$. The maximum value of potential energy is

• A. $K_{0}$
• B. Zero
• C. $\frac{K_{0}}{2}$
• D. Not obtainable

Answer 1

Answer: (A)

$K_{0}$

Answer 2

Since maximum value of $\cos^{2}\omega t$is 1.

$\therefore{Ko{\cos^{2}\omega}_{o}}_{\max}$

Also ${Ko\max}_{\max}$