Question
Mathematics Question on Geometric Progression
For a natural number n, let αn=19n–12n. Then, the value of 57α831α9−α10 is _____.
Answer
Given, αn=19n–12n
Let equation of roots 12 & 19 i.e.
x2−31x+228=0
Where, x=19 or 12
Thus,
57α831α9−α10=57(198−128)31(199−129)−(1910−1210)
=57(198−128)199(31−19)−129(31−12)
=57(198−128)228(198−128)
=57228
=4
So, the answer is 4.