Solveeit Logo

Question

Mathematics Question on Geometric Progression

For a natural number nn, let αn=19n12nα_n = 19n – 12n. Then, the value of 31α9α1057α8\frac {31α_9−α_{10}}{57α_8} is _____.

Answer

Given, αn=19n12nα_n = 19^n – 12^n
Let equation of roots 1212 & 1919 i.e.
x231x+228=0x^2−31x+228=0
Where, x=19x = 19 or 1212
Thus,
31α9α1057α8=31(199129)(19101210)57(198128)\frac {31α_9−α_{10}}{57α_8}=\frac {31(199−129)−(1910−1210)}{57(198−128)}

=199(3119)129(3112)57(198128)=\frac {199(31−19)−129(31−12)}{57(198−128)}

=228(198128)57(198128)=\frac {228(198−128)}{57(198−128)}

=22857= \frac {228}{57}
=4=4

So, the answer is 44.