For a metallic wire, the ratio V/I (V = applied potential di... | PHYSICS - WHEATSTONE BRIDGE | SolveeIt | Solveeit

Today, August 19

Question

For a metallic wire, the ratio V/I (V = applied potential difference, I = current flowing)-

A

Increases or decreases as the temperature rises, depending upon the metal

B

Decreases as the temperature rises

C

Independent of temperature

D

Increases as the temperature rises

Answer

Increases as the temperature rises

Explanation

Solution

$\frac{V}{I}$ = R

and for metals R ↑, on ↑ the temperature.