Question
Chemistry Question on Spontaneity
For A⟶B,ΔH=4Calmol−1ΔS=10Calmol−1K−1 reaction is spontaneous when temperature can be :
A
400 K
B
300 K
C
500 K
D
None of these
Answer
500 K
Explanation
Solution
For A⟶B. This reaction is spontaneous, so ΔG should be negative but for temperature 400K and 300K, ΔG value would not be negative and hence will not be spontaneous. A⟶B ΔH=4kcalmol−1=4000calmol−1 ΔS=10calmol−1K−1 ΔG=ΔH−TΔS=4000−500×10 =4000−5000=−1000 for 500K,ΔG will be negative and hence it will be spontaneous process.