Question

For a given triode$\mu = 20$. The load resistance is 1.5 times the anode resistance. The maximum gain will be

• A. 16
• B. 12
• C. 10
• D. None of the above

Answer 1

Answer: (B)

12

Answer 2

Voltage gain $A_{v} = \frac{\mu}{1 + \frac{r_{p}}{R_{L}}}$

$\because R_{L} = 1.5r_{p} \Rightarrow A_{v} = \frac{\mu}{1 + \frac{r_{p}}{1.5r_{p}}} = \frac{3}{5}\mu = \frac{3}{5} \times 20 = 12$.