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Question: For a gaseous reaction \(2B\to A\) , the equilibrium constant \({{K}_{p}}\) is _____ than \({{K}_{c}...

For a gaseous reaction 2BA2B\to A , the equilibrium constant Kp{{K}_{p}} is _____ than Kc{{K}_{c}} at 298K298K .

Explanation

Solution

Before talking about the answer, you should know what is equilibrium constant, Kp{{K}_{p}} and Kc{{K}_{c}}. Equilibrium constant is the ratio of the amount of products to amount of reactants. Kp{{K}_{p}} is the equilibrium constant for partial pressure and Kc{{K}_{c}} is the equilibrium constant for concentration.

Formula used: Kp=Kc(RT)Δng{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}
where, Kp{{K}_{p}} is the equilibrium constant at pressure, Kc{{K}_{c}} is the equilibrium constant at volume, RR is the universal gas constant, TT is the temperature and Δng\Delta {{n}_{g}} is the change in the number of moles in gaseous form.

Complete step by step answer:
For a gaseous reaction,
2BA2B\rightleftharpoons A
The change in the number of gaseous moles,
Δng\Delta {{n}_{g}} = Total number of moles in product – Total number of moles in reactant
Δng=nPnR\Delta {{n}_{g}}={{n}_{P}}-{{n}_{R}}
Δng=12\Delta {{n}_{g}}=1-2
Δng=1 Accordingtotheformula,\Delta {{n}_{g}}=-1 \\\ According to the formula,{{K}{p}}={{K}{c}}{{(RT)}^{\Delta {{n}{g}}}}Substitutingthegivenvalues,weget, Substituting the given values, we get, {{K}{p}}={{K}{c}}{{(RT)}^{-1}}Therefore, Therefore,{{K}{p}}islessthanis less than{{K}_{c}}$ .

Hence, for a gaseous reaction 2BA2B\to A , the equilibrium constant Kp{{K}_{p}} is less than Kc{{K}_{c}} at 298K298K .

Additional information:
Kp{{K}_{p}} is defined as the equilibrium constant for the partial pressure of the reaction. Kp{{K}_{p}} is used to express the relationship between partial pressure of products and partial pressure of reactants.
Kc{{K}_{c}} is defined as the ratio of concentration of products to that of reactants, each raised to the power equals to stoichiometric coefficients.
Equilibrium constant is defined as the ratio of the products and reactants.
There are several characteristics of equilibrium constant and they are as follows:
The catalyst changes the rate of reaction, but it does not change the value of equilibrium constant.
If the reaction is reversed, then the value of equilibrium constant is the reciprocal of the one in the forward reaction.

Note: The change in number of moles can be calculated from the difference of moles of products and the moles of reactants.
Kp{{K}_{p}} and Kc{{K}_{c}} both are unitless quantities.