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Question

Chemistry Question on Chemical Kinetics

For a first order reaction, to obtain a positive slope, we need to plot {where [A][A] is the concentration of reactant AA}

A

log10[A]vst - \log_{10} [A] \,vs \,t

B

loge[A]vst - \log_{e} [A] \,vs \,t

C

log10[A]vslogt \log_{10} [A] \,vs \,\log t

D

[A]vst[A] \, vs\,t

Answer

loge[A]vst - \log_{e} [A] \,vs \,t

Explanation

Solution

For a first order reaction to obtain a positive slope a, graph is plotted between loge[A]vst-\log _{e}[A] v s t.