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Question

Chemistry Question on Chemical Kinetics

For a first order reaction the rate constant is 6.909 min1min^{-1}. The time taken for 75% conversion in minutes is

A

32log2\frac{3}{2} \, log \, 2

B

23log3\frac{2}{3} \, log \, 3

C

23log2\frac{2}{3} \, log \, 2

D

32log34\frac{3}{2} \, log \, \frac{3}{4}

Answer

23log2\frac{2}{3} \, log \, 2

Explanation

Solution

For first order reaction,
k=2.303tlogaaxk = \frac{2.303}{t} \, log \, \frac{a}{a-x}
6.909=2.303tlog100100756.909 = \frac{2.303}{t} \, log \, \frac{100}{100-75}
t=2.3036.909log4t = \frac{2.303}{6.909} \, log \, 4
=13log22= \frac{1}{3} \, log \, 2^2
=23log2= \frac{2}{3} \, log \, 2