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Question

Chemistry Question on Chemical Kinetics

For a first order reaction A(g)2B(g)+C(g){A(g) \to 2B(g) + C(g)} at constant volume and 300K300\, K, the total pressure at the beginning (t=0)(t = 0) and at time tt are P0P_0 and PtP_t, respectively. Initially, only AA is present with concentration [A]0[A]0, and t1/3t_{1/3} is the time required for the partial pressure of AA to reach 1/3rd1/3^{rd} of its initial value. The correct option(s) is (are) (Assume that all these gases behave as ideal gases)

A

B

C

D

Answer

Explanation

Solution

A2B+C t=0P0 t=tP0P2PP\begin{matrix}&A&\to&2B&+&C\\\ t=0&P_{0}&&-&&-\\\ t=t&P_{0}-P&&2P&&P\end{matrix}
P0+2P=PtP_0 + 2P = P_t
K=1tInP0P0P=1tInP0P0P=1tInP0P0(PtP0)2K = \frac{1}{t} In \frac{P_{0}}{P_{0} - P} = \frac{1}{t} In \frac{P_{0}}{P_{0} - P} = \frac{1}{t} In \frac{P_{0}}{P_{0} - \frac{\left(P_{t} - P_{0}\right)}{2}}
K=1tIn2P03P0PtKt+In2P0=In(3P0Pt)K = \frac{1}{t} In \frac{2P_{0}}{3P_{0} - P_{t}} \Rightarrow -Kt + In 2P_{0} = In \left(3P_{0} - P_{t}\right) and t1/3=1KInP0P0/3=1KIn3t_{1/3} = \frac{1}{K} In \frac{P_{0}}{P_{0}/3}= \frac{1}{K} In 3 = constant
Rate constant does not depends on concentration