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Question

Chemistry Question on Chemical Kinetics

For a first order reaction, A(g)B(g)A(g) \rightarrow B(g) at 35C35^{\circ} C, the volume of AA left in reaction vessel at various times are given below. [Given data : log(5/4)=0.096\log (5 / 4)=0.096. What is the value of rate constant?

A

0.02231 min1\min^{-1}

B

0.04231 min1\min^{-1}

C

0.06231 min1\min^{-1}

D

0.08231 min1\min^{-1}

Answer

0.02231 min1\min^{-1}

Explanation

Solution

For a first order reaction,

A(g)B(g) at 35CA(g) \longrightarrow B(g) \text { at } 35^{\circ} C

The rate constant kk is expressed as

K=2303tlogC0C=230310log2520K =\frac{2303}{t} \log \frac{ C _{0}}{ C }=\frac{2303}{10} \log \frac{25}{20}
=230310log54=230310×0.096=\frac{2303}{10} \log \frac{5}{4}=\frac{2303}{10} \times 0.096
=0.0221min10.02231min1=0.0221\, \min ^{-1} \simeq 0.02231\, \min ^{-1}