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Question

Chemistry Question on Equilibrium

For a diprotic acid, which of the following is true for first and second ionization constants? (Ka1(K_{a_1} and Ka2K_{a_2} ).

A

Ka1=Ka2K_{a_1} = K_{a_2}

B

Ka1>Ka2K_{a_1} > K_{a_2}

C

Ka2>Ka1K_{a_2} > K_{a_1}

D

Ka2Ka1K_{a_2} \ge K_{a_1}

Answer

Ka1>Ka2K_{a_1} > K_{a_2}

Explanation

Solution

For a diprotic acid, further ionization is difficult,
therefore
Ka1>Ka2K _{a_1} > K_{a_2}