Question

For a constant collector-emitter voltage of 8 V, the collector current of a transistor reached to the value of 6 mA from 4 mA, whereas base current changed from 20 μA to 25 μA value. If transistor is in active state, small signal current gain (current amplification factor) will be

• A. 240
• B. 400
• C. 0.0025
• D. 200

Answer 1

Answer: (B)

400

Answer 2

The correct answer is (B) : 400
$β = \frac{ΔI_C}{ΔI_B}$
$= \frac{(6-4)×10^{-3}}{(25-20)×10^{-6}}$
$= \frac{2}{5}×10^3$
= 400