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Question: For a common emitter circuit if \[{{{I}_{C}}}/{{{I}_{E}}}\;=0.98\] then current gain for common emit...

For a common emitter circuit if IC/IE  =0.98{{{I}_{C}}}/{{{I}_{E}}}\;=0.98 then current gain for common emitter circuit will be
(A) 4.94.9
(B) 9898
(C) 4949
(D) 9.89.8

Explanation

Solution

In a transistor, emitter current is equal to the sum of collector current and base current; and the current gain for the common-emitter circuit is ratio of collector current to base current.
Formula used:
The current gain β\beta for a common-emitter circuit is given by:
β=ICIB\beta =\dfrac{{{I}_{C}}}{{{I}_{B}}}
Here IC{{I}_{C}}implies the collector current and IB{{I}_{B}} implies the base-current.

Complete step by step answer:
The ratio of collector current to emitter current, ICIE=0.98\dfrac{{{I}_{C}}}{{{I}_{E}}}=0.98
So, IC=0.98IE{{I}_{C}}=0.98{{I}_{E}}
In a transistor, emitter current is equal to the sum of collector current and base current, that is,
IE=IB+IC{{I}_{E}}={{I}_{B}}+{{I}_{C}} …..(i)
Where IE{{I}_{E}} is the emitter current, IB{{I}_{B}} is the base current and IC{{I}_{C}} is the collector current.
Substitute the value of IC{{I}_{C}} in equation (i):
IE=IB+0.98IE{{I}_{E}}={{I}_{B}}+0.98{{I}_{E}}…..(ii)
Rearrange equation (ii) to get the value of base current IB{{I}_{B}} in terms of IE{{I}_{E}} :

& {{I}_{E}}={{I}_{B}}+0.98{{I}_{E}} \\\ & {{I}_{B}}={{I}_{E}}-0.98{{I}_{E}} \\\ & {{I}_{B}}=0.02{{I}_{E}} \\\ \end{aligned}$$ Now, current gain, $$\beta =\dfrac{{{I}_{C}}}{{{I}_{B}}}$$ Substitute $${{I}_{C}}=0.98{{I}_{E}}$$ and $${{I}_{B}}=0.02{{I}_{E}}$$ in the current gain formula: $$\beta =\dfrac{0.98{{I}_{E}}}{0.02{{I}_{E}}}=49$$. Therefore, current gain for the common emitter circuit is $$49$$. Hence, option C is the correct answer. **Additional information:** In a common emitter circuit, the change in collector current due to change in base current, causes a change in collector-emitter voltage and the voltage drop across the load resistor, because collector supply voltage is fixed. In a transistor connected in CE mode input current is $${{I}_{B}}$$ and output current is $${{I}_{C}}$$. The d.c. current gain depends on the collector current and temperature. The ratio of collector current to emitter current is called transistor alpha $$\alpha $$. Usually in god transistors $$\alpha $$ ranges from $$0.98$$ to $$0.988$$. **Note:** Always remember that current gain is the ratio of output current to the input current so it has no units.Most of the students get confused in it.