Question

For a chemical reaction $X \rightarrow Y$ the rate of reaction increases by a factor of $1.837$ when the concentration of X is increased by $1.5$times the order of the reaction with respect to X is

• A. 1
• B. $1.5$
• C. 2
• D. $2.5$

Answer 1

Answer: (B)

$1.5$

Answer 2

Initially rate $(r_{1}) = k\lbrack X\rbrack^{n}$ …… (i)

(let n be the order of reaction)

Then, $r_{1} \times 1.837 = k(1.5X)^{n}$ …. (ii)

Dividing (ii) by (i)

$1.837 = (1.5)^{n}$

$\therefore n = 1.5$

Thus, order of reaction is $1.5$