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Question: For a chemical reaction A \[\to \]products, the rate of disappearance of A is given by: \(\dfrac{-\p...

For a chemical reaction A \to products, the rate of disappearance of A is given by: CAt=K1CA1+K2CA\dfrac{-\partial {{C}_{A}}}{\partial t}=\dfrac{{{K}_{1}}{{C}_{A}}}{1+{{K}_{2}}{{C}_{A}}} at low CA{{C}_{A}} the reaction is of the __ order with rate constant. (Assume K1,K2{{K}_{1}},{{K}_{2}} are lesser than 11 )

Explanation

Solution

Chemical kinetics basically deals with the different aspects of a chemical reaction. It deals with the rate of change of the reaction. It helps us to understand the rate of reaction and how it changes with certain conditions. It helps to analyse the mechanism of the reaction.

Complete step-by-step answer: During a chemical reaction, when a reaction starts, it decreases the amount of the reactant and increases the amount product in the reaction. Rate of disappearance of reaction tells us about how an amount of reactant decreases with time.
Order of the reaction is defined as power of the concentration of the reactant in a chemical reaction. For example, the rate of first order reaction depends only on one concentration of the reactant.
In this question, the rate of disappearance of A is given by:
CAt=K1CA1+K2CA\dfrac{-\partial {{C}_{A}}}{\partial t}=\dfrac{{{K}_{1}}{{C}_{A}}}{1+{{K}_{2}}{{C}_{A}}}
This is equation 11
We also know that CAt=K[A]n\dfrac{-\partial {{C}_{A}}}{\partial t}=K{{\left[ A \right]}^{n}}
This is equation 22
Where, CA{{C}_{A}} is the concentration of A
KK is the rate constant
nn is the order of the reaction
Now we will equate equation 11 and 22, we get
CAt=K1CA1+K2CA=K[A]n\dfrac{-\partial {{C}_{A}}}{\partial t}=\dfrac{{{K}_{1}}{{C}_{A}}}{1+{{K}_{2}}{{C}_{A}}}=K{{\left[ A \right]}^{n}}
Now, it is given that K1,K2<1{{K}_{1}},{{K}_{2}}<1
Hence we can say that K2CA<<1{{K}_{2}}{{C}_{A}}<<1
Therefore, 1+K2CA11+{{K}_{2}}{{C}_{A}}\approx 1
We can also write equation 22 like this:
CAt=K1CA1\dfrac{-\partial {{C}_{A}}}{\partial t}=\dfrac{{{K}_{1}}{{C}_{A}}}{1}
Now, we will equate both the values of disappearance of A, we get
K1CA=K[A]n{{K}_{1}}{{C}_{A}}=K{{\left[ A \right]}^{n}}
Hence, we can see that the value of nn will be 11
Therefore, this proves that this reaction is first order.

Note: There are many factors that affect rate of reaction:
Concentration of the reactant: the increase in the concentration of the reactant will increase the colliding particle which further increases the rate of the reaction.
Temperature: if we increase the temperature then the collision between the reactant molecules per second increases which further increases the rate of reaction.
Solvent: the nature of the solvent affects the rate of reaction of the solute particles.