Question

For a chemical reaction A ¾® Products, the rate of disappearance of A is given by :

– $\frac{dC_{A}}{dt}$= $\frac{K_{1}C_{A}}{1 + K_{2}C_{A}}$At very low C_A, the reaction is of the ...... order with rate constant...... :

(Assume K₁, K₂ are lesser than 1)

• A. I, K₁/K₂
• B. I, K₁
• C. II, K₁/K₂
• D. II, K₁/K₁ + K₂

Answer 1

Answer: (B)

I, K₁

Answer 2

– $\frac{dC_{A}}{dt}$ = $\frac{K_{1}C_{A}}{1 + K_{2}C_{A}}$

At very low C_A : 1 >> K₂C_A ; (1 + K₂V_A) » 1

\ rate = – $\frac{dC_{A}}{dt}$ = K₁C_A ; Rate constant = K₁

order = 1