Question

For a certain reaction the variation of the rate constant with temperature is given by the equation

ln kt = ln k0 + $\left( \frac{In3}{10} \right)$ t (t ³ 0⁰C)

The value of the temperature coefficient of the reaction rate is therefore

• A. 4
• B. 3
• C. 10
• D. 2

Answer 1

Answer: (B)

3

Answer 2

$\frac{k_{t}}{k_{0}} = (TC)^{t - 0/10}$

Taking log gives loge

$k_{t} - \log_{e}{}k_{0} = \frac{t}{10}\log_{e}(TC) \Rightarrow Ink_{t} = Ink_{0} + t$

Comparision indicates $\text{ln }(\text{TC})\text{ = ln 3} \text{==>} \text{TC = 3}$