Question

For a certain reaction the variation of rate constant with temperature is given by the equation

ln k_t = lnk₀ + $\frac{(\mathcal{l}n3)t}{10}$ (t ³ 0ºC)

The value of temperature coefficient of the reaction is -

• A. 0.1
• B. 1
• C. 10
• D. 3

Answer 1

Answer: (D)

3

Answer 2

$\frac{k_{t}}{k_{0}}$= $µ^{\frac{t - 0}{10}}$

log_e k_t – log_e k₀ = $\frac{t}{10}$log (µ)

ln k_t = ln k₀ + $\left( \frac{\mathcal{l}n(µ)}{10} \right)$ t

\ µ = 3