Question

For a cell reaction involving a two electron change, the standard emf of the cell is found to be 0.295 V at 25⁰C. The equilibrium constant of the reaction at 25⁰C will be :

• A. $\text{1 × 1}\text{0}^{\text{-10}}$
• B. $\text{29.5 }\text{×}\text{ 1}\text{0}^{\text{-2}}$
• C. 10
• D. 1 × 1010

Answer 1

Answer: (D)

1 × 1010

Answer 2

$\text{0 = 0.295 -}\frac{\text{0.059}}{2}\text{ logK} ; \text{log K = 10} \text{K = 1}\text{0}^{\text{10}}.$