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Question

Chemistry Question on Equilibrium

For a cell involving one electron Ecell=0.59VE^\ominus cell=0.59V at 298 K, the equilibrium constant for the cell reaction is: [Given that 2.303RTF\frac{ 2.303 RT }{F} =0.059V=0.059 V atT298KT 298 K]

A

1.0×1021.0\times 10^{2}

B

1.0×1051.0\times 10^{5}

C

1.0×10101.0\times 10^{10}

D

1.0×10301.0\times 10^{30}

Answer

1.0×10101.0\times 10^{10}

Explanation

Solution

The correct option is (C) :1.0×10101.0\times 10^{10}