Question

For, α, β, γ, δ ∈ $\mathbb{N},$ if $∫\left((\frac{x}{e})^{2x}+(\frac{e}{x})^{2x}\right)log_e\,xdx=$ $\frac{1}{\alpha}(\frac{x}{e})^{βx}-\frac{1}{γ}(\frac{e}{x})^{δx}+c,$ Where $e=\displaystyle\sum_{n=10}^{∞}\frac{1}{n!}$ and C is constant of integration, then α + 2β + 3γ - 4δ is equal to

• A. -8
• B. -4
• C. 1
• D. 4

Answer 1

Answer: (D)

4

Answer 2

The correct option is(D ): 4