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Question: For \(25.3g\) of sodium carbonate \(N{a_2}C{O_3}\) is dissolved in enough water to make \(250ml\) of...

For 25.3g25.3g of sodium carbonate Na2CO3N{a_2}C{O_3} is dissolved in enough water to make 250ml250ml of solution. If sodium carbonate dissociates completely molar concentration of sodium ions Na+N{a^ + } and carbonate ions are respectively (molar mass of Na2CO3=106gmol−1N{a_2}C{O_3} = 106gmo{l^{ - 1}} )?

Explanation

Solution

In chemistry, concentration shows how a substance is strong or reactive. The molar concept is used to find the concentration, mass, and moles of the substance. There is a constant value of one mole that is Avogadro constant.

Complete step by step answer:
Before, calculating the concentration of sodium and carbonate ions, let's have a look at molar mass.
Molar mass - It states that the mass of a sample substance that is in grams divided by the molecular weight of the substance. It represents MM and its SI unit is kg/molkg/mol.
Molarity - It defines the concentration of the chemical substance. It measures in terms of per unit volume of solution.
Solution -It a mixture of solute and solvent. The solute is the substance dissolved in the solvent.
We have given, Na2CO3→2Na++CO3−−N{a_2}C{O_3} \to 2N{a^ + } + C{O_3}^{ - - }
Here, one mole of sodium carbonate is equal to two moles of sodium and one mole of carbonate.
molar mass Na2CO3N{a_2}C{O_3} = 106gmol−1106gmo{l^{ - 1}}
volume -250ml250ml
Firstly, find the number of moles of Na2CO3N{a_2}C{O_3}
n=25.3106=0.238n = \dfrac{{25.3}}{{106}} = 0.238
When we dissociate it, we get two times sodium moles and one time carbonate.
sodium moles = 2×0.238=0.4762 \times 0.238 = 0.476
carbonate moles= 1×0.238=0.2381 \times 0.238 = 0.238
Now, find the molarity =moles of solutevol of solution\dfrac{{moles\,of\,solute}}{{vol\,of\,solution}}
molarity of sodium = 0.476250×10−3\dfrac{{0.476}}{{250 \times {{10}^{ - 3}}}} =1.910M1.910M
molarity of carbonate = 0.238250×10−3\dfrac{{0.238}}{{250 \times {{10}^{ - 3}}}} =0.955M0.955M
Therefore, the concentration of sodium and carbonate ions are 1.910M1.910Mand 0.955M0.955M.

Note:
The solution has two types that are Homogeneous solution and Heterogeneous solution. Homogeneous - A solution in a fixed ratio or composition is known as homogeneous. Heterogeneous - A solution is not in a fixed ratio or composition that is known as the heterogeneous solution. The common unit of molarity is mol per liter.