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Question

Chemistry Question on Stoichiometry and Stoichiometric Calculations

For 14g14\, g of COCO the wrong statement is :

A

it occupies 2.24 litres at NTP

B

it corresponds to 12\frac{1}{2} mole of CO

C

it corresponds to same mole of CO and nitrogen gas

D

it corresponds to 3.01×1023 3.01\times 10^{23} molecules of CO

Answer

it occupies 2.24 litres at NTP

Explanation

Solution

We know that 14gmCO=1428=0.5mol14\, gm CO =\frac{14}{28}=0.5\, mol Therefore, it corresponds to 12\frac{1}{2} mole of CO and nitrogen gas. 0.50.5 mol is equivalent to 3.01×10233.01 \times 10^{23} molecules.