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Question

Chemistry Question on States of matter

For 1 mol of an ideal gas at a constant temperature TT, the plot of (logP)(log\, P) against (logV)(log\, V) is a (PP: Pressure, VV: Volume)

A

Straight line parallel to x-axis

B

Straight line with a negative slope

C

Curve starting at origin

D

Straight line passing through origin

Answer

Straight line with a negative slope

Explanation

Solution

According to Boyle's law, PV=PV = constant logP+logV=\therefore log \,P + log \,V = constant logP=logV+log\, P = - log\, V + constant Hence, the plot of log PP vs log VV is straight line with negative slope.