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Question

Chemistry Question on Gibbs Free Energy

Following reaction takes place in Daniell cell:
Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s);Ecell0=1.1VZn(s)+Cu^{2+} (aq) \rightarrow Zn^{2+} (aq) + Cu(s); E^0_{cell} = 1.1V
Standard Gibbs energy, in this case will be

A

-2123.0 KJ/mol

B

-212.3 KJ/mol

C

+212.3 KJ/mol

D

+21227 KJ/mol

Answer

-212.3 KJ/mol

Explanation

Solution

The correct option is (B): -212.3 KJ/mol