Question

Following mechanism has been proposed for a reaction.

2A + B D + E

Step -1 A + B C + D – (slow)

Step -2 A + C E – (fast)

The rate law expression for the reaction is:

• A. Rate = K[A]2 [B]
• B. Rate = K [A] [B]
• C. Rate = K [A]2
• D. Rate = K[A][C]

Answer 1

Answer: (B)

Rate = K $A$ $B$

Answer 2

A + B $\overset{\quad Slow\quad}{\rightarrow}$ C + D

A + B $\overset{\quad fest\quad}{\rightarrow}$

R = k (1) (2) [slow step is determining step].