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Question

Mathematics Question on Statistics

Following are the marks obtained, out of 100100, by two students Ravi and Hashina in 1010 tests. Who is more intelligent and who is more consistent?

A

Ravi is more consistent and intelligent.

B

Hashina is more consistent and intelligent.

C

Ravi is more consistent and Hashina is more intelligent.

D

Ravi is more intelligent and Hashina is more consistent.

Answer

Ravi is more consistent and Hashina is more intelligent.

Explanation

Solution

For Ravi, let assumed mean = 45 σ1=di2n(din)2\sigma_{1}=\sqrt{\frac{\sum d_{i}^{2}}{n}-\left(\frac{\sum d_{i}}{n}\right)^{2}} =169910(910)2=\sqrt{\frac{1699}{10}-\left(\frac{-9}{10}\right)^{2}} =169.90.81=169.09=13.00=\sqrt{169.9-0.81}=\sqrt{169.09}=13.00 Now, mean (x1ˉ)=Σxin=44110=44.1\left(\bar{x_{1}}\right)=\frac{\Sigma x_{i}}{n}=\frac{441}{10}=44.1 For Hashina, let assumed mean = 55 σ2=596810(2010)2=596.84=592.8=24.34 \sigma_{2}=\sqrt{\frac{5968}{10}-\left(\frac{-20}{10}\right)^{2}}=\sqrt{596.8-4}=\sqrt{592.8}=24.34 Now, mean (xˉ2)=53010=53\left(\bar{x}_{2}\right)=\frac{530}{10}=53 For Ravi, C.V.1=σ1x1×100=1344.1×100=29.47C.V._{1}=\frac{\sigma_{1}}{x_{1}}\times100=\frac{13}{44.1}\times100=29.47 For Hashina, C.V.2=σ2xˉ2×100=24.3453×100=45.92C. V._{2}=\frac{\sigma_{2}}{\bar{x}_{2}}\times100=\frac{24.34}{53}\times100=45.92 Hence, Ravi is more consistent and intelligent.