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Question

Question: Focus of the parabola \({(y - 2)^2} = 20(x + 3)\) is \( \left( a \right){\text{ }}\left( {3, - 2} ...

Focus of the parabola (y2)2=20(x+3){(y - 2)^2} = 20(x + 3) is

(a) (3,2) \left( a \right){\text{ }}\left( {3, - 2} \right)

(b) (2,3) \left( b \right){\text{ }}\left( {2, - 3} \right)

(c) (2,2) \left( c \right){\text{ }}\left( {2,2} \right)

(d) (3,3)\left( d \right){\text{ }}\left( {3,3} \right)

Explanation

Solution

Hint: Compare the given equation of parabola with the standard form and find the values of x0x_0, y0y_0 and a. Substitute these values in focus of parabola (x0+a,y0)(x_0+a, y_0) to find the required solution.

Complete step by step answer:

As, we know that the standard equation of parabola is (yy0)2=4a(xx0){\left( {y - {y_0}} \right)^2} = 4a\left( {x - {x_0}} \right). In which,

\Rightarrow Vertex = (x0,y0)(x_0,y_0) and,

\Rightarrow Focus of parabola is (x0+a,y0)(x_0+a, y_0)

(y2)2=20(x+3) \Rightarrow {\left( {y - 2} \right)^2} = 20\left( {x + 3} \right)..............................(1)

Comparing equation (1) with standard equation of parabola we get,

x0=3, y0=2\Rightarrow {x_0} = - 3,{\text{ }}{y_0} = 2 and a = 5

So, focus of the parabola in equation 1 will be,

focus=(3+5,2)=(2,2)\Rightarrow {\text{focus}} = \left( { - 3 + 5,2} \right) = \left( {2,2} \right)

Hence the correct option for the question will be c.

NOTE: - Whenever this type of question is given then compare x0y0{x_0}{\text{, }}{y_0} and a with the standard equation of parabola. And then find the required parameter by putting values.